32. Given that log 2 to the base 10 = x and log 3 to the base 10 = y then the value of log 60 to the base 10
sivaprasath:
2x + y + log 5 base 10
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54
[Note: No need to define the base if it's 10.]
Given that,
→ log(2) = x
→ log(3) = y
We have to find,
log(60)
We have to use the concept,
"log(ab) = log(a) + log(b)"
Now,
log(60)
=> log(6 • 10)
=> log(6) + log(10)
=> log(2 • 3) + 1 [log(10) = 1]
=> log(2) + log(3) + 1
=> x + y + 1
Hence, x + y + 1 is the answer.
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