Question

32. If u = tan−1

(

x

5+y

5

x+y

) then

(a) tanu is a homogeneous function of order 4 in x and y

(b) If tanu = v then x

∂v

∂x + y

∂v

∂y = 2v

(c) If tanu = v then x

∂v

∂x + y

∂v

∂y = 4tanu

(d) If tanu = v then ∂v

∂x = (1 + tan2u)

∂u

∂x

(e) x

∂v

∂x + y

∂v

∂y = Sin(2u)​

Answer 1

12345

Step-by-step explanation:

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