Question

32- In fig. OACB is quadrant of a circle with centre 0 and radius 8 cm. If OD=5cm,Find the area of the quadrant OACB​

Answer 1

Answer:

Area of quadrant OACB=

4

Area of Circle

=

4

π×r

2

=

4

1

×

7

22

×3.5×3.5 =9.625cm

2

(ii)

Area of the shaded region = Area of Quadrant −Area of △BDO

=9.625−(

2

1

×3.5×2)

=6.125cm

2