32. In the figure, AO = OD and OB = OC. Then
(A) AB = CD (B) ZABC = ZBCD
(C) triangle BAD = triangle ADC (D) All of these
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In△AOD&△BCO
=>OD=OC (given)
OA=OB(given)
∠AOD=∠COB (vertically opposite)
=>△AOD≅△BOC
∠OAD=∠OBC(angles corresponding to congruent sides)
[∵ AD & BC make equal angles with the same line AB]
HenceAD∣∣BC
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