Question

32 question please answer my question ​

Answer 1

$\sin( \alpha ) = \frac{3}{4}$

$\sqrt{ \frac{ (\csc\alpha) {}^{2} - \cot{}^{2} \alpha }{ \sec {}^{2} \alpha - 1} }$

$\sqrt{ \frac{1}{ \tan {}^{2} \alpha } }$

$= \cot( \alpha )$

$\sqrt{ \csc {}^{2} \alpha - 1 }$

$= \sqrt{ \frac{16}{9} - 1}$

$\sqrt{ \frac{7}{9} } = \frac{ \sqrt{7} }{3}$

Answer 2

Answer:

Step-by-step explanation: