Question

32. The value of n in, MnO4 - + 8H+ + ne- =>Mn2+ +

4H2O is
a. 5
b. 4
c. 3
d. 2​

Answer 1

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option A 5 electrons.

equation:

MnO4^- + 8H^+ 5e^- ----> Mn^+2 +4H2O

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Answer 2

Answer:

The Correct Answer would be a.5. For the reaction:

MnO₄⁻ + 8H⁺ + ne⁻ →  Mn²⁺, the value of n, that is number of electrons will be 5.

Explanation:

In the above chemical reaction, we are asked to balance the reaction on both sides. For this, we need to balance the total charge on both sides of the reaction, i,e., Number of Electrons on Left-Hand Side = Number of Electrons on Right-Hand Side.

Now, we have the reaction as MnO₄⁻ + 8H⁺ + ne⁻ →  Mn²⁺.

Taking a closer look, we see that we have to add electrons on the left side as this whole reaction is an Oxidation reaction, where the element gets oxidized.

We know that if the reaction is Oxidation, we add electrons to balance the reaction on the left side. Hence, proceeding:

Let the no. of electrons to be added is n.

On the left side, the total charge is:

-1 + 8(+1) + (-n)      =       7 - n

On the right side, it is = 2

Hence, for balance, 7-n = 2

This gives n=5 as the answer.