321a is divisible by 11 .find the value of smallest natural number a
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when we divide ...321/11=29+2.
the remainder is 2 ,.
we can't set it to be divisible by 11 by multiplying value less than 11.
so smallest value is a=11
the remainder is 2 ,.
we can't set it to be divisible by 11 by multiplying value less than 11.
so smallest value is a=11
Anonymous:
ok
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