Question

32g of o2, and 3g of hydrogen are mixed and kept in a vessel of 760mm pressure and 0c the total volume occupied by the miscture

Answer 1

mol of O2 would be 1 and mol of H2 would be 3 thus total no of mole =4
P=1 atm = 760 mm Hg and T=273K and takes R=1/12
PV=NRT
V=NRT/P
=4×1/12×273
=91L