Math, asked by devrukhkarvaishnavi2, 7 hours ago

32x-33y =97 :33x-32y=98 solve the equation ​

Answers

Answered by pallavinsharma124
1

Answer:

32x-33y =97 --- 1

33x-32y=98 --- 2

Subtract equation 1 from 2

x - y = 1 or x = 1 + y

Substitute value ( x = 1 + y ) in equation 1

32x - 33y = 97

32 ( 1 + y ) - 33y = 97

32 + 32y - 33y = 97

32 - y = 97

32 - 97 = y

y = - 65

x = 1 + y

x = 1 + ( -65 )

x = 1 - 65

x = -64.

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