Question

33. A body is thrown vertically upwards and takes
5 seconds to reach maximum height. The distance
travelled by the body will be same in
(1) 1st and 10thsecond (2) 2nd and 8th second
(3) 4th and 6th second (4) Both (2) 8 (3)
​

Answer 1

Answer:

(1)

Explanation:

Body reach at maximum height after 5 sec then

v = u−gt ⇒ 0 = u − g×5 ⇒ u =50m/s2

Distance travelled by the body in 1st sec = distance travelled in t =1s - distance travelled in t=0s

⇒ h =ut − 12gt2 = 45m (up)

Distance travelled by the body in 10th sec = distance travelled in t =10s - distance travelled in t=9s

⇒h = ut +12gt2 = 45m (down)

So, first option will be right

Answer 2

Answer:

the correct answer is option 1