Question

33) Construct a square having length of the diagonals as 8cm.
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Answer 1

Step-by-step explanation:

The sides of a square are equal. So, let's call the length x

Use the pythagoras' theroem

Square the sides and add them together

x^2 + x^2 = 8^2

2x^2 =64

x^2= 64/2 = 32

x = _/32

x = 4_/2

Answer is 5.66

Answer 2

⇒  Draw a line segment AB of 8 cm. (Fig. 1)

⇒  Draw the perpendicular bisector of AB. Mark the point of intersection of AB and its perpendicular bisector as O. (Fig. 2)

⇒  Draw a circle with AB as diameter and with center at O. Mark the points of intersection of the circle and the perpendicular bisector of AB as C and D each. (Fig. 3)

⇒  Draw AC, BC, AD and BD. Thus a square ABCD having length of the diagonals 8 cm each will get. (Fig. 4)

AB = CD = 8 cm.