Question

33) From each corner of a square of a 4 cm a quadrant of a circle of radius 1 cm is
cut and also a circle of diameter 2 cm is cut as shown in fig. Find the area of the
remaining portion of the square.
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Answer 1

Answer:

$Area \: of \: shaded \: region = Area \: of \: square  \: ABCD − Area \: of \: 4 \: quadrants − Area \: of \: circle \: with \: diameter \:  2 cm \\ Area \: of \: square = 4×4={16cm}^{2} \\ Area \: of \: sector = \frac{Ѳ}{360} \times \pi \times {r}^{2} \\ Area \: of \: 4 \: quadrants =4× \frac{90}{360} ×π×1×1 = { 3.14cm}^{2} \\Area \: of \: circle=π× {r}^{2}  =π×1×1= { 3.14cm}^{2} \\ ∴ Area \: of \: shaded \: region =16−6.28 = {9.72cm}^{2}$

Step-by-step explanation:

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