Question

33. If, for a positive integer n, the quadratic equation,
x(x + 1) +(x + 1)(x+2)+....+(x+n-1)(x + n) = 10n
has two consecutive integral solutions, then n is
equal to :

(A) 10 (B) 11 (C) 12 (D)9
​

Answer 1

Answer:

9 is the answer of this question

Answer 2

Answer:

it's 11 B

Step-by-step explanation:

apply formulas