Math, asked by dhaliwalakashdeep422, 8 months ago


33) In a rhombus ABCD, AC = 6cm and BD =8cm , find the lengths of each sides.

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Answered by satyam2004b
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Practical Geometry

Construction of Special Quadrilaterals

Construct a rhombus ABCD wh...

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Construct a rhombus ABCD where AC=6 cm and BD=7 cm. Then, perimeter of rhombus ABCD is:

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ANSWER

1. Draw a diagonal AC=6 cm.

2. Draw a perpendicular bisector of AC, let the perpendicular bisector and AC intersects at O (∵ Diagonals of rhombus intersects at right angle)

3. Taking O as centre and half of the length of another diagonal (i.e 3.5 cm) as radius, mark arc on the perpendicular bisector at both sides of AC. Name these intersection points as B and D

4. Join AB,AD,BC,CD.

5. ABCD is the required rhombus.

6. Measure the length of any one side (∵ All sides of rhombus are equal), which come out to be 4.6 cm

Perimeter of rhombus =4× side =4×4.6=18.4 cm

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