Question

33. The enthalpy of formation of ammonia is
-46.0 kJ mol-1. The enthalpy for the reaction
2N2(g) + 6H2(g) → 4NH3(g) is
(1). -46 kJ
(2) 46 kJ
(3) 184 kJ
(4) -184 kJ​

Answer 1

33. The enthalpy of formation of ammonia is

-46.0 kJ mol-1. The enthalpy for the reaction

2N2(g) + 6H2(g) → 4NH3(g) is

(1). -46 kJ

(2) 46 kJ

(3) 184 kJ✔️✔️✔️

(4) -184 kJ