33. The sum of 3rd and 7th terms of an arithmetic progression is 6 and their product is 8
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Step-by-step explanation:
the sum of third and seven term is 6
a + 2d + a + 6d = 6
2a + 8d = 6
a + 4d = 3
now the 5th term is 3
now the product is 8
(a+2d)(a+6d) =8
a²+ 6ad + 2ad + 12d² = 8
a(a+6d)+2d(a+6d)= 8
(a+2d)(a+6d) = 8
sharan2268:
AP series?
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