33. What is the minimum diameter of the wire which is connected with lift having
mass of 1000kg and accelerating uniformly at 1.2 ms 2 rates? The wire can bear
maximum stress of 1.4 x 108 Nm. Take g = 9.8 ms.
Answers
Answered by
1
Explanation:
Tension in wire = T= 1000 (9.8 + 1.2) = 11000N
maximum stress = T/ λr min² = 110000 x 7 /22 x r min²
r min² = 50²/ (10⁴)²
minimum radius = 50 x 10⁻⁴
minimum diameter= 2 x rmin
= 2 x 50 x 10⁻⁴
= 100 x 10⁻⁴m
= 0.01m
tag me as brainliest if it helped
Similar questions