Question

34.2 gram of glucose is dissolved in 400 gram of water calculate percentage by mass of glucose solution​.

solve it step by step.....plzzz

Answer 1

Answer:

a/c to question, 34.2g of glucose is dissolved in 400g of water.

so, mass of glucose (solute)= 34.2g

mass of water (solvent) = 400g

mass of solution = mass of solute + mass of solvent

so, mass of glucose solution = mass of glucose + mass of water

= 34.2g + 400g

= 434.2g

now, percentage by mass of glucose solution =(mass of glucose/mass of solution) × 100

= (34.2/434.2) × 100

= 7.87 %

hence, percentage by mass of glucose solution is 7.87%

[extra point : you can also find molality of glucose. as you know molality = no of mole of solute/mass of solvent in kg .

here, mass of solute = 34.2g

molar mass of glucose (solute) = 180g/mol

mass of solvent (water) = 400/1000 =0.4kg

so, molality = (34.2/180)/0.4 = 0.475m]

i wish that i helped you if not sorry