Physics, asked by nutron5417, 11 months ago

34. A dielectric slab of dielectric constant k is placed between the plates of a parallel plate capacitor carrying

Answers

Answered by ritik12336
0

Answer:

Explanation:

When a dielectric of dielectric constant K is inserted into the plates the induced charge is given by the relation:

q' = q(1 - 1/K)

some information about dielectrics:

A dielectric  is a very poor conductor of electricity because they have no loose electrons. When a dielectric is placed in an electric field, electric charges do not flow through the material as they do in an electrical conductor but only slightly shift from their average equilibrium positions causing dielectric polarization. Because of dielectric polarization, positive charges are displaced in the direction of the field and negative charges shift in the opposite direction. This creates an internal electric field that reduces the overall field within the dielectric

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