How many molecules of water are produced by the combustion of 3.00 g of methane
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Answer:
3/8 NA = 3/8 × 6.023 × 10^23 molecules of H2O
Explanation:
CH4 + 2O2 -----> CO2 + 2H2O
So, we can easily conclude that 1mole of CH4 gives 2mole of H2O.
3.0g of CH4 = 3/16 moles
therefore , H2O produced = 2× 3/16 moles
= 3/8 moles
= 3/8 NA molecules
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