Question

34 g of NH3 is decomposed to give 6 g of hydrogen
and an unknown amount of nitrogen. What will be the
mass of N2 formed?
2 NH3
- N2 + 3 H2

Answer 1

Answer: 14 g of N2 gas is created.

2 NH3 ----> N2 + 3H2

2 moles =  1 mole : 3 moles

34 g       =  ? grams : 6 grams

1 mole of NH3 = 17 g, therefore 2 moles of NH3 = 34 g

1 mole of H2 =  2g , therefore 6 grams = 3 moles of Hydrogen gas

2 NH3 ----> N2 + 3H2

2 moles   =  1 mole : 3 moles

2 moles    = ? moles : 3 moles.

Thus we can see that 1 mole of Nitrogen is created.

1 mole of Nitrogen gas =  14 g

                     

Answer 2

The mass of $N_{2}$  formed is 28 g.

Explanation:

Given:

34 g of $NH_{3}$ is decomposed to give 6 g of hydrogen and an unknown amount of nitrogen.

$2NH_{3} \rightarrow N _{2}+3H_{2}$

To Find:

The mass of $N_{2}$  formed.

Solution:

$2NH_{3} \rightarrow N _{2}+3H_{2}$

As given- 34 g of $NH_{3}$ is decomposed to give 6 g of hydrogen and an unknown amount of nitrogen.

For $NH_{3}$ , M = 17

Moles of ammonia $=\frac{34}{17} =2$

2 moles of ammonia will produce 1 mole of nitrogen and 3 moles of hydrogen.

1 mole  of nitrogen=1×28= 28 g.

3 moles of hydrogen=3×2= 6 g (as given)

Thus,the mass of $N_{2}$  formed is 28 g.

PROJECT CODE#SPJ3