Math, asked by yuktamittal11, 1 month ago

(34) If A and B leave their houses at 10:00, walking
directly towards each other, they meet at 10:10. If A
leaves his house at 10:00 and B leaves his house at
10:03, again walking towards each other, they meet at
10:11. At what time will B reach A's house if he leaves
his house at 10:00?
a) 10: 15
b) 10: 20
c)10: 24
d)10: 12
e) 10 : 30​

Answers

Answered by yashawinisingh
8

Answer:

10:20 --it is the right answer

because B will take 10 minutes to reach the point they met and 10 minutes to reach at house of A

Step-by-step explanation:

its your answer

hope it is helpful

THANKS☺☺☺☺☺

Answered by ahiraza52
0

Answer:

Step-by-step explanation:

let x is the total distance

speed of A is a and speed of B is b so

distance=speed * time

x=a*10+b*10 case one equation 1

x=a*11+b*8 case two equation 2

subtracting 1-2

a=2b

put in equation 1

a=30b

for 10b distance b took 10 minute

so for 30b disctance b will take 30 minute

so answer is 10:30

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