Question

34. If the zeroes of the quadratic polynomial x2 + (a+1) x +b are 2 and -3 then
find a and b.​

Answer 1

Hey There!!

Given Polynomial

x² + ( a + 1) x + b = 0

- As 2 and 3 are the zeroes of the given polynomial so they must satisfy the given equation . So we put both values one by one!

Put x = 2

=> 2² + ( a + 1 ) 2 + b = 0

= 4 + 2a + 2 + b = 0

= 2a + b + 6 = 0 ...............(1)

Put x = -3

=> (-3)² + ( a + 1) -3 + b =0

= 9 - 3a - 3 + b=0

= b - 3a + 6 = 0.................(2)

Multiply (1) × 3 and (2)×2 and then add

= 6a - 6a + 3b + 2b + 18 + 18 = 0

= 5b = -36

b = -36/5

Put the value of b and uh can get a also