34. If the zeroes of the quadratic polynomial x2 + (a+1) x +b are 2 and -3 then
find a and b.
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Hey There!!
Given Polynomial
x² + ( a + 1) x + b = 0
- As 2 and 3 are the zeroes of the given polynomial so they must satisfy the given equation . So we put both values one by one!
Put x = 2
=> 2² + ( a + 1 ) 2 + b = 0
= 4 + 2a + 2 + b = 0
= 2a + b + 6 = 0 ...............(1)
Put x = -3
=> (-3)² + ( a + 1) -3 + b =0
= 9 - 3a - 3 + b=0
= b - 3a + 6 = 0.................(2)
Multiply (1) × 3 and (2)×2 and then add
= 6a - 6a + 3b + 2b + 18 + 18 = 0
= 5b = -36
b = -36/5
Put the value of b and uh can get a also
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