35.5 g of chlorine occupies 11,200 cm³ at S.T.P. 35.5 g of chlorine occupies 11,200 cm³ at S.T.P. We have to calculate the atomicity of chlorine. 35.5 g of chlorine occupies 11,200 cm³ at S.T.P. We have to calculate the atomicity of chlorine. As we know 1 mole of any particular substance is equal to 1 g molecular mass of it. i.e., 1 mole of substance = 1 g molecular mass of it 1 gram of chlorine occupies how much ? 1 gram of chlorine occupies how much ? ==> 11200cm³ 1 gram of chlorine occupies how much ? ==> 11200cm³ Calculating grams of chlorine that will occupy 22,400 cm³ at S.T.P. 1 gram of chlorine occupies how much ? ==> 11200cm³ Calculating grams of chlorine that will occupy 22,400 cm³ at S.T.P.==> 22400 × 35.5 / 11200 1 gram of chlorine occupies how much ? ==> 11200cm³ Calculating grams of chlorine that will occupy 22,400 cm³ at S.T.P.==> 22400 × 35.5 / 11200 ==> 22400 × 355 / 11200 × 10 1 gram of chlorine occupies how much ? ==> 11200cm³ Calculating grams of chlorine that will occupy 22,400 cm³ at S.T.P.==> 22400 × 35.5 / 11200 ==> 22400 × 355 / 11200 × 10 ==> 224 × 355 / 112 × 10 1 gram of chlorine occupies how much ? ==> 11200cm³ Calculating grams of chlorine that will occupy 22,400 cm³ at S.T.P.==> 22400 × 35.5 / 11200 ==> 22400 × 355 / 11200 × 10 ==> 224 × 355 / 112 × 10 ==> 224 × 71 / 112 × 2 1 gram of chlorine occupies how much ? ==> 11200cm³ Calculating grams of chlorine that will occupy 22,400 cm³ at S.T.P.==> 22400 × 35.5 / 11200 ==> 22400 × 355 / 11200 × 10 ==> 224 × 355 / 112 × 10 ==> 224 × 71 / 112 × 2 ==> 112 × 71 / 112 1 gram of chlorine occupies how much ? ==> 11200cm³ Calculating grams of chlorine that will occupy 22,400 cm³ at S.T.P.==> 22400 × 35.5 / 11200 ==> 22400 × 355 / 11200 × 10 ==> 224 × 355 / 112 × 10 ==> 224 × 71 / 112 × 2 ==> 112 × 71 / 112 ==> 71 ------------------------------------------------- Thus, gram molecular mass would be 71g . Thus, gram molecular mass would be 71g .Now at last we would calculating the atomicity by using this formula: Thus, gram molecular mass would be 71g .Now at last we would calculating the atomicity by using this formula: ==> Atomicity = Molecular mass / Atomic mass Thus, gram molecular mass would be 71g .Now at last we would calculating the atomicity by using this formula: ==> Atomicity = Molecular mass / Atomic massAgain given, Thus, gram molecular mass would be 71g .Now at last we would calculating the atomicity by using this formula: ==> Atomicity = Molecular mass / Atomic massAgain given,• Molecular mass = 71g Thus, gram molecular mass would be 71g .Now at last we would calculating the atomicity by using this formula: ==> Atomicity = Molecular mass / Atomic massAgain given,• Molecular mass = 71g • Atomic mass = 35.5 g Thus, gram molecular mass would be 71g .Now at last we would calculating the atomicity by using this formula: ==> Atomicity = Molecular mass / Atomic massAgain given,• Molecular mass = 71g • Atomic mass = 35.5 g Applying the required values: Thus, gram molecular mass would be 71g .Now at last we would calculating the atomicity by using this formula: ==> Atomicity = Molecular mass / Atomic massAgain given,• Molecular mass = 71g • Atomic mass = 35.5 g Applying the required values: ==> 71 / 35.5 Thus, gram molecular mass would be 71g .Now at last we would calculating the atomicity by using this formula: ==> Atomicity = Molecular mass / Atomic massAgain given,• Molecular mass = 71g • Atomic mass = 35.5 g Applying the required values: ==> 71 / 35.5 Solving now, Thus, gram molecular mass would be 71g .Now at last we would calculating the atomicity by using this formula: ==> Atomicity = Molecular mass / Atomic massAgain given,• Molecular mass = 71g • Atomic mass = 35.5 g Applying the required values: ==> 71 / 35.5 Solving now,==> 71 × 10 / 355 Thus, gram molecular mass would be 71g .Now at last we would calculating the atomicity by using this formula: ==> Atomicity = Molecular mass / Atomic massAgain given,• Molecular mass = 71g • Atomic mass = 35.5 g Applying the required values: ==> 71 / 35.5 Solving now,==> 71 × 10 / 355==> 71 × 2 / 71 Thus, gram molecular mass would be 71g .Now at last we would calculating the atomicity by using this formula: ==> Atomicity = Molecular mass / Atomic massAgain given,• Molecular mass = 71g • Atomic mass = 35.5 g Applying the required values: ==> 71 / 35.5 Solving now,==> 71 × 10 / 355==> 71 × 2 / 71 ==> 2 => atomicity of chlorine is 2
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Aswan High Dam is a rock-fill dam located at the northern border between Egypt and Sudan. The dam is fed by the River Nile and the reservoir forms Lake Nasser. Construction for the project began in 1960 and was completed in 1968. It was officially inaugurated in 1971.
Answer:
==> Atomicity = Molecular mass / Atomic massAgain given,• Molecular mass = 71g • Atomic mass = 35.5 g Thus, gram molecular mass would be 71g .Now at last we would calculating the atomicity by using this formula: ==> Atomicity = Molecular mass / Atomic massAgain given,• Molecular mass = 71g • Atomic mass = 35.5 g Applying the required values: Thus, gram molecular mass would be 71g .Now at last we would calculating the atomicity by using this formula: ==> Atomicity = Molecular mass / Atomic massAgain given,• Molecular mass = 71g • Atomic mass = 35.5 g Applying the required values: ==> 71 / 35.5 Thus, gram molecular mass would be 71g .Now at last we would calculating the atomicity by using this formula: ==> Atomicity = Molecular mass / Atomic massAgain given,• Molecular mass = 71g • Atomic mass = 35.5 g Applying the required values: ==> 71 / 35.5 Solving now, Thus, gram molecular mass would be 71g .Now at last we would calculating the atomicity by using this formula: ==> Atomicity = Molecular mass / Atomic massAgain given,• Molecular mass = 71g • Atomic mass = 35.5 g Applying the required values: ==> 71 / 35.5 Solving now,==> 71 × 10 / 355 Thus, gram molecular mass would be 71g .Now at last we would calculating the atomicity by using this formula: ==> Atomicity = Molecular mass / Atomic massAgain given,• Molecular mass = 71g • Atomic mass = 35.5 g Applying the required values: ==> 71 / 35.5 Solving now,==> 71 × 10 / 355==> 71 × 2 / 71 Thus, gram molecular mass would be 71g .Now at last we would calculating the atomicity by using this formula: ==> Atomicity = Molecular mass / Atomic massAgain given,• Molecular mass = 71g • Atomic mass = 35.5 g Applying the required values: ==> 71 / 35.5 Solving now,==> 71 × 10 / 355==> 71 × 2 / 71 ==> 2 => atomicity of chlorine is 2