35. (a) Calculate the work done by a man of mass 50 kg when he climbs up a ladder of
height 10 m. (g = 9.8 m s2).
Answers
Answered by
2
Answer:
Work done =energy consume
P. E=mgh
=50*9.8*10
=4900j
Answered by
0
Answer:
Work is - 4900 J.
Step-by-step explanation:
m = 50 kg
s = 10 m
g = 9.8 m/s²
F = m g
=> F = 50 * (-9.8)
=> F = - 490 N
W = F * s
=> W = (-490) * 10
=> W = - 4900 J
Here, negative sign is because direction of force and direction of displacement are opposite. So work is negative.
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