Question

35. (a) Calculate the work done by a man of mass 50 kg when he climbs up a ladder of
height 10 m. (g = 9.8 m s2).​

Answer 1

Answer:

Work done =energy consume

P. E=mgh

=50*9.8*10

=4900j

Answer 2

Answer:

Work is - 4900 J.

Step-by-step explanation:

m = 50 kg

s = 10 m

g = 9.8 m/s²

F = m g

=> F = 50 * (-9.8)

=> F = - 490 N

W = F * s

=> W = (-490) * 10

=> W = - 4900 J

Here, negative sign is because direction of force and direction of displacement are opposite. So work is negative.