Question

35. Find the greatest number of six digits which is a perfect square. Find the
square roots of this number.
please fast answer me​

Answer 1

Answer:

998001

Step-by-step explanation:

Largest six-digit number = 999,999

Try to find out the square root of 999999 using "Long Division Method".

You will get: Quotient = 999, Remainder = 1998

We want to find the greatest "6 digit" number which is a perfect square, so we will subtract the remainder from 999999.

999999 - 1998 = 998001

Hence, the greatest "6 digit" number which is a perfect square is 998001.

Find the square root of 998001 using "Long Division Mehtod".

You will get: $\sqrt998001}$ = 999

Hence, square root of 998001 is 999.