Question

35. For a telescope in normal adjustment, the length
of telescope is found to be 27 cm. If the
magnifying power of telescope, at normal
adjustment is 8, the focal lengths of objective and
eye piece are respectively
(1) 24 cm, 3 cm (2) 27 cm, 8 cm
(3) 12 cm, 6 cm (4) 27 cm, 9 cm
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Answer 1

Answer:

option 1

Explanation:

f = focal length of objective

f'= focal length of eye piece

For normal adjustment, m =f/f'. and

L = f+ f'

8= f/ f'

f= 8f'..........(1)

as L= f+ f'

27= f+f'...............(2)

From equation 1 and 2,

f' = 3cm

f= 24 cm

Answer 2

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