Math, asked by AnahitaK, 21 days ago

35 men could do a certain work in 40 days. If after 4 days, 7 of the men suddenly left, in how many days will the REMAINING work be completed?
Please help with the answer

Answers

Answered by karsikata
3

Answer:

44 days

Step-by-step explanation:

35men=40 days

1 man=1440 days

28 men=50 days

After 4 days the remaing work will be done in 44 days.

Answered by nilesh102
20

Given data : 35 men could do a certain work in 40 days. After 4 days, 7 of the men suddenly left.

To find : In how many days will the REMAINING work be completed?

Solution : Now, a/c to given data;

  • 35 men can do a work in 40 days

Hence,

  • 35 men's 1 day's work = 1/40

and

  • 1 men's 1 day's work = 1/(40 * 35)

Now,

  • 35 men's 4 day's work = (1/40) * 4 = 4/40 = 1/10

Here, we have to find out remaining work after 4 day's, So,

  • Remaining work = complete work - 35 men's 4 day's work
  • Remaining work = 1 - (1/10) = (10 - 1)/10 = 9/10

Here, we know that, after 4 days, 7 of the men suddenly left the work, so

  • Total men left = 35 - 7 = 28 men

Now,

  • 28 men's 1 day's work = (1/40 * 35 ) * 28
  • 28 men's 1 day's work = 28/(40 * 35)
  • 28 men's 1 day's work = 28/1400
  • 28 men's 1 day's work = 1/50

Therefore, 28 men's can do 1/50 in 1 day.

Now,

➜ Time taken by men's to complete work = (Remaining work)/(28 men's 1 day's work)

➜ Time taken by men's to complete work = (9/10)/(1/50)

➜ Time taken by men's to complete work = (9/10) * 50

➜ Time taken by men's to complete work = 9 * 5

➜ Time taken by men's to complete work = 45 days

Answer : Hence, the remaining work will be completed in 45 days.

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