3500 = 5000 (1+r/100)^9 find the value of r
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1 st year
Principal, P=Rs.5000
Time, T=1 year
Rate of interest ,R=6%
∴simple Interest, SI= 100
PPT = 100
5000×10×6 =Rs.300
∴Amount=P+SI=Rs.5300
2nd year
Principal = Amount of 1st year=Rs.5300
Rate of interest =8%
Time =1 year
∴ Interest = 1005300×1×8 =Rs.424
∴ Amount =Rs.(5300+424)=Rs.5724
The interest of 2nd year is the required compound interest. So, C.I=rs.424 and the required amount is Rs.5724
hope it helps
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