Question

36.5g of HCL is present in 500ml of the solution. Its molarity will be ?

Answer 1

Explanation:

molarity=3.65⋅g36.5⋅g⋅mol−1500⋅mL×10−3

Answer 2

Answer:

1.45955

Explanation:

first

3.65+36.5=40.15

mol-1500mlfirst

c.f.

a

change 1500mililitre into gram

1ml = 1gram

40.15- 1500

1459.55

third step 10 is to the power minus 3

1459.55×10minus3

minus power the point get left increase

1.45944 ANSWER