Question

36.An electric dipole consists of two opposite charges of magnitude 1micro coloumb separated by a distance of 2cm.The dipole is placed in an electric field 10power-5v/m.The maximum torque does the field exert on the dipole is

Answer 1

Hi friend,

The formula is

Torque (tau)= pE sinϴ

Here E =10^-5
ϴ=90°

P=q×2d
=10^-6 ×2×10^-2

P=2×10^-8
Sub all the known values...

τ =2×10^-8 ×10^-5 ×1 [sin 90°=1]

τ = 2×10^-13 C m.

Hope I helped you a little!!!

Answer 2

The torque's value is 4×$10^{-13}$ Cm.

Step-by-step process

Given:

The electric charge; q= 1 um

The distance; d= 2cm= 2×$10^{-2}$m

Electric field= $10^{-5}$ v$m^{-1}$

To find = Torque

Solution:

The formula for torque is = pEsinθ

Since the dipole is perpendicular to electric field; θ=90°

The value of p(dipole moment) is =2×q×d

=2×$10^{-6}$× 2×$10^{-2}$

=4×$10^{-8}$  Cm

The torque is given  =pEsinθ

Putting the values:

Torque= 4×$10^{-8}$ ×  $10^{-5}$ ×sin90

=4×$10^{-13}$ ×1

4×$10^{-13}$ Cm.

Result:

The torque's value is 4×$10^{-13}$ Cm.

(#SPJ2)