36. Five positive integers are in AP. The sum of 3 middle terms is 24 and product of first and fift
term is 48. Find the terms of AP.
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Step-by-step explanation:
Series be a−2d,a−d,a,a+d,a+2d
The sum of first 3 terms
a−d+a+a+d=24
3a=24
a=24÷3
a=8
(a−2d)(a+2d)=48
a2−4d2=48
substitute a=8
64−4d2=48
4d2=64−48
d2=16
d=2
Therefore, series are 4,6,8,10,12
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