Question

36] From a point on the ground the angle of elevation of the top
of a tower is xº. Moving 150 meters away from that point
the angle of elevation was found to be yº. If tan x=3/4 and
tan y=5/7, find the height of the tower.
77 D.​

Answer 1

hope it helps.

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Answer 2

The height of the tower is 2250m

1.let the height of tower be h

2.initial distance from the foot of tower be k

3.tanx=h/k

4.tany=h/k+150

3/4=h/k

k=4h/3

5/7=h/k+150

5k+750=7h

750 =h/3

therfore h=2250m