Chemistry, asked by DEKISUGI32, 10 months ago

36 g water and 828g ethyl alcohol from an ideal solution . the mole fraction of water in it

Answers

Answered by OkiGema

Answer:

0.0759

Explanation:

no.of moles of water=36/18=2

no.of moles of ethyl alcohol=828/34=24.35

mole fraction of water=2/(2+24.35)=2/26.35=0.0759

DEKISUGI32: this answer is not in the option

OkiGema: what are options

OkiGema: write here

DEKISUGI32: a = 1.0

DEKISUGI32: b = 0.7

DEKISUGI32: c = 0.4

DEKISUGI32: d = 0.1

OkiGema: sorry i re calculate it but my is same

DEKISUGI32: its ok

Answered by kusumanarayanaswamy

Answer:

0.1

Explanation:

no.of moles of water=36÷18

no.of moles of ethyl alcohol=828÷46

=18

mole fraction of water=no. of mole of water÷no of water+no.of mole of ethyl alcohol

=2÷2+18

2÷20

=0.1

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