36 g water and 828g ethyl alcohol from an ideal solution . the mole fraction of water in it
Answers
Answered by
15
Answer:
0.0759
Explanation:
no.of moles of water=36/18=2
no.of moles of ethyl alcohol=828/34=24.35
mole fraction of water=2/(2+24.35)=2/26.35=0.0759
DEKISUGI32:
this answer is not in the option
what are options
write here
a = 1.0
b = 0.7
c = 0.4
d = 0.1
sorry i re calculate it but my is same
its ok
Answered by
7
Answer:
0.1
Explanation:
no.of moles of water=36÷18
no.of moles of ethyl alcohol=828÷46
=18
mole fraction of water=no. of mole of water÷no of water+no.of mole of ethyl alcohol
=2÷2+18
2÷20
=0.1
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