Question

if secx+ tanx=p then show that p^2-1/p^2+1 =sinx

Answer 1

If secx + tanx =p then

secx- tanx = 1/p as sec²x - tan²x =1

solving these two equations

2secx = p²+1/p

secx = p²+1/2p

tanx = p²-1/2p

sinx = p²-1/p²+1