36. If 3x – 4y = 1 and xy = 6, find the value of 27x3 –
64y3.
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Answered by
3
Answer:
27x3 – 64x3 = (3x)3 – (4y)3
= (3x – 4y)3 (3x – 4y)3 + 3 (3x)(4y) (3x – 4y)
[∵ a3 – b3 = (a – b)3 + 3ab(a – b)
= (5)3 + 36(xy) (3x – 4y) = 125 + 36 (3) (5)
= 125 + 540 = 665
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0
Answer:
665......
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