Question

36. The breadth of a rectangle is 3cm less than the length of the rectangle. If the length is increased by 9 cm and breadth is decreased by 5 cm, the area remains unchanged. Find the dimensions of the rectangle. . I want whole calculation. The writing should be clear if you attach photo .

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

let length = l

breadth = b

Step-by-step explanation:

l=b+3 ---------(1)

l*b = area -----------(2)

subs 1 in 2 we get,

(b+3)(b)=area

$b^{2} +b = area$ ------(3)

now the second case,

(l+9)(b-5)=area

lb-5l+9b-45=area ------------(4)

subs 1 in 4,

(b+3)b-5(b+3)+9b-45=area

$b^{2} +3b-5b-15+9b-45= area$

$b^{2} +7b-60=area$ ------------------(5)

equating 3 and 5 we get,

$b^{2} +b = b^{2} +7b - 60\\b=7b-60\\\\-6b=-60\\\\\ b=10cm$

as breadth is 10cm then length = 10+3

l=13 cm

thus the dimensions are 13cm and 10cm respectively

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