Question

36.
The frictional force acting on 1 kg block is
ju=0.5 ~
1 kg
100 kg 10 N
(Smooth surface)
(2) 2 N
(4) 5 N
(1) 0.1 N
(3) 0.5 N​

Answer 1

Answer:

5 N

Explanation:

N = 1 × g = 10 N

frictional force = uN

= 0.5 × 10

= 5 N