Question

36 x square - 12 ax + a square minus b =0 square by completing the square method​

Answer 1

Step-by-step explanation:

$36 {x}^{2} - 12ax + {a}^{2} - b = 0 = >$

${(6x - a)}^{2} = b = > 6x - a = \sqrt{b} \: or - \sqrt{b}$

x=> (a+√b)/6 or (a-√b)/6. Hope it helps you.