360 cm qube of methane gas diffused through a porous membrane in 15 minutes. under similar conditions, 120 cm qube of another gas diffused in 10 minutes. find the molar mass of the gas.
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Rate of diffusion of methane
r1=Volume of methan eTime of dif fusion of methan e
=360cm315min=24cm3min−1
Molar mass of CH4(M1)=16gmol−1
Unknown Gas
Rate of diffusion of unknown gas
r2=Volume of unknown gasTime of dif fusion
=120cm310min=12cm3min−1
Molar mass of unknown gas (M2)=?
Acording of Graham's law of diffusion,
r1r2=M2M1−−−−√
24cm3min−112cm3min−1=M216gmol−2−−−−−−−−√
Squaring of both sides,
M2=24×24×1612×12=64
Molar mass of the unknown gas =64g.mol−1
Explanation:
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