(3600÷x-3) – (3600÷x) = 40
solve the equation plss!!!!
Answers
Answered by
1
Answer:
Find common denominator
(
3
6
0
0
−
3
)
−
(
3
6
0
0
)
=
4
0
(\frac{3600}{x}-3)-(\frac{3600}{x})=40
(
3
6
0
0
+
(
−
3
)
)
−
(
3
6
0
0
)
=
4
0
(\frac{3600}{x}+\frac{x(-3)}{x})-(\frac{3600}{x})=40
2
Combine fractions with common denominator
(
3
6
0
0
+
(
−
3
)
)
−
(
3
6
0
0
)
=
4
0
(\frac{3600}{x}+\frac{x(-3)}{x})-(\frac{3600}{x})=40
(
3
6
0
0
+
(
−
3
)
)
−
(
3
6
0
0
)
=
4
0
(\frac{3600+x(-3)}{x})-(\frac{3600}{x})=40
3
Re-order terms so that constants are on the left
(
3
6
0
0
+
(
−
3
)
)
−
(
3
6
0
0
)
=
4
0
(\frac{3600+x({\color{#c92786}{-3}})}{x})-(\frac{3600}{x})=40
(
3
6
0
0
−
3
)
−
(
3
6
0
0
)
=
4
0
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