Question

(361)^3+(139)^3/(361)^2-(361×139)+(139)^2​

Answer 1

a³+b³=(a+b)(a²-ab+b²)

(361)³+(139)³=(361+139)(361²-(361×139)+139²)

therefore the solution is 361+139

500

Answer 2

Answer:

It would be 500

Step-by-step explanation:

Given expression,

(361^3 + 139^3)\div (361^2-361\times 139+139^2)

=\frac{361^3 + 139^3}{361^2-361\times 139+139^2}​

Using the formula,

a³ + b³ = (a+b)(a² - ab + b² )

⇒ 361^3 + 139^3=(361 + 139)(361^2-361\times 139+139^2)

By substituting the value,

\frac{361^3 + 139^3}{361^2-361\times 139+139^2}=\frac{(361 + 139)(361^2-361\times 139+139^2)}{361^2-361\times 139+139^2}

= 361 + 139

= 500