Question

36g of glucose is present in 500 g of water then what is the molality
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Answer 1

Answer:0.4m

Explanation:

Molality, m=moles of solute × 1000 / mass of solvent (in g)

= 36× 1000180 × 500 = 0.4m

Answer 2

Given:-

→ Mass of glucose (solute) = 36g

→ Mass of water (solvent) = 500g

To find:-

→ Molality of the solution

Solution:-

→Chemical formula of glucose= C₆H₁₂O₆

• Molar mass of Carbon (C) = 12g

• Molar mass of Hydrogen (H) = 1g

• Molar mass of Oxygen (O) = 16g

Hence, molar mass of glucose :-

= 12×6+1×12+16×6

= 72+12+96

= 180g

Number of moles in 36g of glucose :-

= Given Mass/Molar mass

= 36/180

= 0.2 mole

Now, let's convert the mass of water from

g to kg.

=> 1g = 0.001kg

=> 500g = 500(0.001)

=> 0.5kg

Molality of a solution :-

= Moles of solute/Mass of solvent in kg

= 0.2/0.5

= 0.4 m

Thus, molality of the solution is 0.4 m .