36g water and 828g ethyl alcohol form an ideal solution. The mole
fraction of water in it, is
[MP PMT 2003]
(a) 1.0
(b) 0.7
(c) 0.4
(d) 0.1
DO
.
Answers
Answered by
1
Explanation:
( d.) 0.1
Number of moles of water (n) = 3618 = 2
No. of moles of ethyl alcohol (N) = 82846 = 18
∴ Mole-fraction of water = nn+ N
= 22 + 18 = 220 = 0.1
PLEASE FOLLOW ME...
Similar questions