Math, asked by manshipandey992, 8 months ago

36x2-12ax+(a2-b2)=0find root

Answers

Answered by dharshi8
1

Step-by-step explanation:

(6x)^2 - 12a + (a^2-b^2) = 0

( 6x - a)^2 - b^2) = 0

(6x - a - b) ( 6x - a + b) =0

x = a + b / 6, a - b / 6

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