Question

a car initially at rest reaches a velocity of 50 km/hr in 10 seconds is which acceleration

Answer 1

Given

• Initial velocity (u) = 0
• Final velocity (v) = 50km/h
• Time taken (t) = 10s

Find out

• Acceleration = ?

Solution

➾ Final velocity = 50km/h

➾ v = 50 × 5/18

➾ v = 13.8m/s

As we know that

➾ v = u + at

➾ 13.8 = 0 + a × 10

➾ 13.8 = 10a

➾ a = 13.8/10

➾ a = 1.38m/s²

Hence,

• Acceleration of a car is 1.38m/s²

Additional Information

• s = ut + ½ at² [2nd equation of motion]

• v² = u² + 2as [3rd equation of motion]

$\rule{200}3$

Answer 2

GIVEN :-

•Initial velocity (u) = 0 m/s .

•Final velocity (v) = 50km/hr

•Time (T) = 10sec.

TO FIND :-

• Acceleration = ?

SOLUTION :-

We know that,

=> km/hr = 1000/3600 = 10/36 = 5/18m/s .

=> .°. Final velocity (v) = 50km/hr

=> Final velocity (v) = 50 × 5/18

=> Final velocity (v) = 13.8m/s

Now, apply 1st equation of motion.

=> v = u + at

=> 13.8 = 0 × a × 10

=> a = 13.8/10

=> a = 1.38 m/s².

Therefore, the acceleration of car is 1.38 m/s².