Question

36xsquare-49/81 Factorise?​

Answer 1

Answer:

$\displaystyle{\rightarrow \left(6x+\frac{7}{9}\right)\left(6x-\frac{7}{9}\right)}$

Step-by-step explanation:

Given :

$\displaystyle{36x^2-\frac{49}{81}}$

Rewrite it as :

$\displaystyle{(6x)^2-\left(\frac{7}{9}\right)^2}$

Now using identity :

$\displaystyle{(x^2-y^2)=(x+y)(x-y)$

$\displaystyle{(6x)^2-\left(\frac{7}{9}\right)^2} \\\\\\\displaystyle{\rightarrow \left[(6x)+\left(\frac{7}{9}\right)\right]\left[(6x)-\left(\frac{7}{9}\right)\right]}\\\\\\\displaystyle{\rightarrow \left(6x+\frac{7}{9}\right)\left(6x-\frac{7}{9}\right)}$

Answer 2

Question》 Facetorise

${36x}^{2} - \frac{49}{81}$

ANSWER 》

${36x}^{2} - \frac{49}{81} \\ = ( {6x})^{2} - ( \frac{7}{9} )^{2} \\ (use \: the \: formula \: of \\</h2><h2>{x}^{2} - {y}^{2} = (x + y)(x - y) \\ =(6x + \frac{7}{9} )(6x - \frac{7}{9} ) \\</h2><h2> = (\frac{54x + 7}{9}( \frac{54x - 7}{9} )</h2><h2>(answer)$