Question

37 /13 = 2 + 1/(x+1)/{y+1/z}

Answer 1

37-26/13=1/(x+1)(y+1/z)
11/13=1/(x+1)(y+1/z)
11(x+1)(y+1/z)=13
11(xy+x/z+y+1/z)=13
11(xy+y+x+1/z)=13

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Answer 2

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