Question

37. A+B= 90°, cot B =3/4 , then sin A is
equal to​

Answer 1

Answer:

Step-by-step explanation:

Given, A+B= 90°____(1), cot B =3/4.

Applying cot on both sides in eqn (1),

CotA + Cot B = Cot90

CotA = 0 - 3/4

CotA = 3/4

Using pythagoras thm,

Hyp. = 5

So, SinA = 4/5

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Answer 2

Answer:

Here ,A+B=90 Degree.

taking cot both sides:

cot(A+B)=cot90deg=0

or, (cotAcotB-1)/(cotA+cotB)=0

;or, cotAcotB-1=0

or,cotAcotB=1

or, 3/4 (cotA)=1

so, cotA=4/3

As, cotA=b/p

clearly, b=4k & p=3k

thus, h=5k

hence, sinA=p/h=3k/5k=3/5 ans..

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