Question

37 gm of some primary alcohol were oxidised and this resulted in 44 gm of monobasic carboxylic acid. Draw the possible structural formula of the reaction product​

Answer 1

Answer:

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Answer 2

RCH₂OH + [O] → R-H-C=O + H₂O

R- COOH + [O] → R-OH-C=O

CH₃CH₂OH+2[O]→CH₃COOH+H₂O

Explanation:

• Primary alcohols and aldehydes are normally oxidized to carboxylic acids using potassium dichromate(VI) solution in the presence of dilute sulfuric acid.
• During the reaction, the potassium dichromate(VI) solution turns from orange to green. The potassium dichromate(VI) can just as well be replaced with sodium dichromate(VI).
• Because what matters is the dichromate(VI) ion, all the equations and color changes would be identical.

Primary alcohols are oxidized to carboxylic acids in two stages - first to an aldehyde and then to the acid.

• We often use simplified versions of these equations using "[O]" to represent oxygen from the oxidizing agent.
• The formation of the aldehyde is shown by the simplified equation:

                        RCH₂OH + [O] → R-H-C=O + H₂O

                        R- COOH + [O] → R-OH-C=O